(7分)根據(jù)圖示回答下列問題:

(1)寫出G的結(jié)構(gòu)簡式:                              ;
(2)反應(yīng)③的化學(xué)方程式是                                         ,
反應(yīng)④的化學(xué)方程式是                                             
(3)寫出②、⑤的反應(yīng)類型:②                、⑤                   。
(1)HOOC(CH24COOH(1分)
(2)(2分)
(2分)
(3)消去反應(yīng),    縮聚反應(yīng)       (每空1分)解析:
本題屬于有機合成題。根據(jù)F和G的反應(yīng)得到的生成物結(jié)構(gòu)簡式可判斷,反應(yīng)⑤是縮聚反應(yīng)。因此F是乙二醇,G是1,6-己二酸,結(jié)構(gòu)簡式為HOOC(CH24COOH。氯代烴水解可生成醇,所以C是1,2-二氯乙烷,因此A是乙烯,B是氯氣,通過加成反應(yīng)得到C。根據(jù)D的分子式可判斷,C通過消去反應(yīng)生成D,即D是氯乙烯,結(jié)構(gòu)簡式為CH2=CHCl。氯乙烯甲聚即得到高分子化合物E,結(jié)構(gòu)簡式為
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